64181 Precalculus
Section 03 |
Answer |
Question 1 (5 points) Do Either (a) or (b)
(a) Linear functions problems:
(i) Suppose that f(x) is linear and that f(-2) = 4, f(5) = -3.
Find a formula for f(x). (-2, 4) and (5, -3) -
(ii) Suppose that g(x) is linear with slope passing
through the point (1, 8). Find a formula for g(x).
(iii) Suppose that h(x) is linear with an x-intercept of -7 and a y-intercept of -2.
Find a formula for h(x).
(iv) Suppose that p(x) is linear with x-intercept = 2 and parallel to y = -4x + 2.
Find its formula.
or
(b) Find domain
of the function
The denominator cannot be 0 and the radical cannot be negative. So Domain is all values of x such that Range (not required) is y > 0 (note that there is no value of x that can make y = 0 or negative) |
Question 2 (5 points) Piecewise Function
(a) Sketch the piecewise defined function f(x). Use an open circle to represent a point which is not included an solid dot to indicate a point which is on the graph.
(b) What is the value of x when f(x) = 2? Note that f(x) = 2 for both equations 2 and 3. Equation 2: Equation 3: So x = 1.4142 and 2 for f(x) = 2
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Figure 4.3
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