Lesson 6 - 2.3 #10 Investigation of (a) Graph of both functions: (not the same) (abs value) (b) Comparing table of values -5 -4 -3 -2 -1 0 1 2 3 4 5 5 4 3 2 1 0 1 2 3 4 5 (c) because graphs overlap and they share the same piecewise functions: (d) Graphing	Lesson 6 - 2.3 #11 Investigation of (a) Graph the function (undefined at x = 0) (b) Table agrees with observations in graph -5 -4 -3 -2 -1 0 1 2 3 4 5 -1 -1 -1 -1 -1 U 1 1 1 1 1 (c) Domain is all x except x = 0. The range is -1 and 1 (d) the claim that u(x) = 0 when x = 0 is false since the function is undefined at x = 0.
Lesson 6 - 2.3 #14 Piecewise word problem; 2 linear functions: (a) (minimum area is 0 and maximum is given has 150) (cost change to new formula after 150 sq. ft and maximum area given has 1000) (b) Graph and Domain and Range Domain is Range is ( for 1st domain) and (fro 2nd domain)	Lesson 6 - 2.3 # 16 Supermarket refund policy (a piecewise functions): refund, y as a function of difference between scanner and price, x). (a) The smallest difference, the smaller the refund: Is $0.01 (not 0.0) refund is $1.00 + $0.01 = $1.01 (b) Piecewise function is: (1) (2) (3) (c) Find x when y = $9.00 - Only equation (3) can give a refund value high enough, so solve: