Lesson 3a Linear Functions

Section 1.3 #2 Determine if a table of values represents a linear function.

The function is a linear function since for every (constant rate throughout the function)

Section 1.3 # 7 Identify y-intercept and slope fro a linear formula,

y-intercept is $29.99 and

slope, m is 0.05 (cost per minutes)

Section 1.3 #12 Find formula from linear problem statement.

Given population in 2002 is 18,310 (P0) and growth rate per year (t) is 58 people.

Formula is P = 18310 + 58t.

Section 1.3 #13 Properties of Linear Function from table of values.

(a) Table is linear function since constant rate:

(b) Linear plot with points (0, 50) & (100, 75)

(c) Slope is 0.25 (a) and (d) When x = 0, C = $50, setup cost

Section 1.3 #18 Linear Depreciation Formula

Given: Cost from new Car is $21,000 and depreciates by $10,500 in 3 years.

So yearly depreciation is 10500/3 = $3500

Depreciation means negative rate, so

m = -$3,500.

Formula for depreciation since new is

V(t) = 21000 - 3500t

Section 1.3 #20 Interpreting linear tuition cost, T with respect to number of credits for part-time students.

(a) T when C = 8 is T = 300 + 200(8) = $1900

(b) C when T = 1700 is 1700 = 300 + 200C

C = (1700 - 300) / 200 = 7

(c) Table of values for C = 1 to 12 credits

C 0 2
.. 10 11 12
T 500 700   2,300 2,500 2,700
T/C 500 350   230 227 225

(d) The lowest cost per credits is when C = 12 of 225

(e) The cost of 300 represents fixed cost like registration cost

(f) The 200 represents the rate or cost for each additional credits