Lesson 24 - 8.1 - 8.3 Composition of Function and Inverse

Pg. 347: 5,6,29,51 and

Lesson 24 - 8.1 #5 Composition from formula:

Given

Find

So

Lesson 24 - 8.1 #6 Composition from formula:

Given

Find

Lesson 24 - 8.1 #29 Composition from formula:

Given graph below:

(a) f(f(1)) = f(2) = 4

(b) g(g(1)) = g(3) = 1

(c) f(g(2)) = f(2) = 4

(d) g(f(2)) = g(4) = 0

Lesson 24 - 8.1 #51 Composition from formula:

Given

Find

So

Inverse Functions

Pg. 359: 33,37,43 and

Lesson 24 - 8.2 #33 Solve by using the inverse function:

Solve

by quadratic formula:

Lesson 24 - 8.2 #37 Inverse Function -

The function y = sin t fails the horizontal line test except on certain intervals, here is an example of one:

Lesson 24 - 8.2 #43 Study of the Area of a circle and its inverse function -

(a) Area: (d) The inverse function is ; however the true Domain and range is positive

(b) Graph of function shown below which fails horizontal line test.

(c) Since r >= 0 only domain of is valid.

Domain and Range

(d) Graph of function and inverse

(e) Domain A(r) is r > = 0 and Range is A >= 0

Domain of Inverse, r(A) is same as Range of A(r), r > = 0 etc. So inverse only with restricted domain and range.

Pg. 367: 2,6,7,12,21,31 - Composition of Functions

Lesson 24 - 8.3 #2 Composition of Function:

Given

Lesson 24 - 8.3 #6 Composition of function:

Given

Find

Lesson 24 - 8.3 #7 Composition of Function:

Given:

(a)

(b)

(c)

(d)

Lesson 24 - 8.3 #12 Composition of Function:

Given:

(a)

(b)

(c)

(d)

Lesson 24 - 8.3 #21 Composition of Function:

Revenue = # customers times price per customer

R(i) = n(i) x p(i)

= (50000 - 2500i)(15 + i)

Max. profit occurs when i = 2.5 (quadratic solution to R(i), vertex (h, k) where h = 2.5)

Max. price = 15 + I = $17.50

Lesson 24 - 8.3 #31 Composition of Function from word problem:

(a) pop size = sun of men and women

(b) tot money = amt. women make times number of women