Pg. 264: 1,5,9,16,19,25,31,34,38

Lesson 20 - 6.5 #1, State period, amplitude, and midline of sinusoidal function with formula Midline, D is -8 Amplitude, A = 7 and	Lesson 20 - 6.5 #5, What are the horizontal and phase shift (should also know how to state period, amplitude, and midline) of sinusoidal function with formula For , phase shift is -4 For , horizontal shift is - 4/3 (D = -5, A = 2 and B = 3 or P = )
Lesson 20 - 6.5 #16, State period, amplitude, and midline of sinusoidal function with graph shown and write a formula: From graph: A = 2, D = 2, P = 12, so B = Function is -sin(x)	Lesson 20 - 6.5 #19, State period, amplitude, and midline of sinusoidal function with graph shown and write a formula: From graph: A = 3, D = 3, P = 4, So B = Function is - cos(x)
Lesson 20 - 6.5 #25, Ferris Wheel problem: Find formula if A = 10 (radius), D = 14 (radius + 4 m), P = 2 minutes (1 cycle, so B = ) and boarding is at 6 o'clock position (t = 0 at 12 o'clock position); so phase shift of 90 deg to left or counterclockwise. When t = 0, 12 o'clock suggest a cos(x), however formulas must be in sin(x):	Lesson 20 - 6.5 #31, Animal population problem: Find formula if A = 450 [(Max - Min) / 2], D = 1750 [(Max - Min) / 2], P = 12 months (1 cycle, so ). Note low = 1300 (t = 0, Jan 1) and high = 2200 (t = 6, Jul. 1). (a) Formula is (c) From Graph P = 1500 at about t = 1.9 and 10.1

Lesson 20 - 6.5 #9, Graph one period of . Note B = 1 so , A = 4, and D = 0 and since cos at t = 0 at maximum of 4.

Lesson 20 - 6.5 #34, Transformation of trig function. Transformation is

Lesson 20 - 6.5 #38, Pressure with t through pipes is a periodic function given: P(max) = 230 and P(min) = 90, when t = 0, P = 90 and cycles 5 times per hour (B), so 1 cycle in 60/5 = 12 minutes. (b) D = (90 + 230) / 2 = 160 A = 230 - 160 = 70 Function is a - cos(t) since min at t = 0. Formula is (c) between , Find when P = 115 graphically. Ans. when t = 1.67 minutes