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Confidence Interval by Example Series |
Given the need to find the confidence interval about a statistical parameter
from a sample of size n; the following examples illustrate
the correct methodology to determine the confidence interval:
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For mean: For mean For proportion :
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Example 1. Find the 95% confidence interval for the mean of the
boiling point of water from a sample of size 32 with mean of 212.5
and standard deviation of 1.2.
Given: The level of confidence is 95% or Probability of 0.95,
then
and
.
The mean,
and the standard deviation, s
or
,
n=32
(large sample size so use standard normal distribution for estimates).
(from Standard
Normal Table, taking the absolute or positive value of z
obtained from the table with corresponding
probability of 0.025).
Confidence
Interval is :![]() ![]() |
Solution: The population mean is between:
Lower Limit | Upper Limit |
:![]() |
:![]() |
212.08 | 212.92 |
Given: The level of confidence is 98% or Probability of 0.98,
then
and
.
The mean,
and the standard deviation, s
= 0.4 , n
=18 (small sample size so use student t distribution
for estimates).
(from Student
t distribution Table, taking value of t = 0.01 with a d.f.
= 20 -1 = 19, t0.01 = 2.57).
Confidence
Interval is :![]() ![]() |
Solution: The population mean is between:
Lower Limit | Upper Limit |
:![]() |
:![]() |
98.56 | 99.04 |
Given: The level of confidence is 90% or Probability of 0.90,
then
and
.
The mean, ,
n
- x = 100-52>5 (large sample size so use standard normal distribution
for estimates).
So q = 1- p = 0.48.
(from Standard
Normal Table, taking the absolute or positive value of z
obtained from the table with
corresponding probability of 0.05).
Confidence
Interval is :![]() ![]() ![]() |
Solution: The population mean is between:
Lower Limit | Upper Limit |
:![]() |
::![]() |
0.44 | 0.60 |
![]() |