Theory |
by Example Series Linear Functions |
Since Linear Increase of the form: Pt = P0 + m t
Point #1 (t, P) = 2, 25.1) and Point #2 = (10, 25.5)
First find
P0: Using point #1: 25.1 = P0 + 0.05 (2), P0 = 25 millions
So the initial population was 25 millions
(linear formula is P = 25 + 0.05 t )
Question 2. The value of a new car purchased in 1995 depreciates
linearly from $16,500 to
$14000 after 5 years, what is the rate of depreciation of the car
in $ per year?
Rate of depreciation is a decreasing function so rate m is negative:
( formula would be: P = 16,500 - 500 t)
Question 3. Number of students, N, attending Ridgemount Community
College increases
at a constant rate over a 4 year period. From the graph shown below
write a formula for
Number of Students as a function of year, t since 1985.
Point 1: (1985, 850)
Point 2: (1988, 1006)
Linear Growth so formula is : Nt = b + m t
Find m: using 1988 and 1985 data:
Since b = 850 (Number of students at time = 0, 1985) formula is Nt = 850 + 52 t
Question 4. The cost of yearly tuition, C in $ for students at Ridgemount
Community College increases
at a constant rate over a 4 year period. From the information shown
in the table below write a formula
for yearly tuition cost as a function of time, t in years since
1985.
C = 3206 + 105 t
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Linear Growth so formula is : Ct = b + m t
Find m: using 1988 and 1985 data:
Since b = 3206 (Tuition at time = 0, 1985) formula is Ct = 3,206 + 105 t
Question 5. The population, Pt, millions, of a country
was observed the second year at 10.1 millions
and 11.5 millions the tenth year, where t is years. What was the
initial population of this country
when it was observed if it grows linearly?
Since Linear Increase of the form: Pt = P0 + m t
First find
P0: Using point #1: 10.1 = P0 + 0.175 (2), P0 = 9.75 millions
So the initial population was 9.75 millions
Question 6. The value of a farm equipment purchased in 1987 depreciates
linearly from $20,000 to
$16,250 after 5 years, what is the rate of depreciation of the equipment
per year?
Rate of depreciation is a decreasing function so rate m is negative:
( formula would be: P = 20,000 - 750 t)
Question 7. The value of a new car purchased in 1990 depreciates
linearly from $18,500 to $16,000
after 5 years, write a formula for the depreciation of the car as
a function of time in year?
Since V0 = 18,500, Vt = 18,500 - 500 (t)
Question 8 A woodworker goes into business selling carved wooden
horses; if the total cost,
C in $ for carving n horses is shown in the table below: write a
formula that shows
the cost as a function of n horses:
n, number of horses | C, total cost ($) |
1 | 5350 |
2 | 5700 |
5 | 6750 |
10 | 8500 |
Linear since rate:
So cost at n = 0: Using (1, 5350):
So formula: C = 5000 + 350 (n) (check when n = 10: C = 5000 + 350(10)=8500)
Question 9. Find the formula for the linear depreciation of the value
of an automobile
from $25,000 to $20,450 in 7 years. V = b + m(t) (linear model)
At t = 0, b = $25,000 (start time of depreciation)
So